How to pass optional params in url in django python

Question

i have 2 type of URL crud/app and other is crud/app/2 here you can see id can be optional, so how to apply this type of URL pattern, here i have added my code,

app_name = 'crud'
urlpatterns = [
    path('',views.index, name='index'),
    path('add/<:id>',views.add, name='add'),
]

Bloodmallet · Accepted Answer · 2019-04-26 12:26:49Z

1

urls.py

app_name = 'crud'
urlpatterns = [
    path('',views.index, name='index'),
    path('add',views.add, name='add_empty'),
    path('add/<int:id>',views.add, name='add_id'),
]

views.py

def add(request, id=None):

    # if id was provided
    if id:
        [...]
    else:
        [...]

But you shouldn't overwrite function names (id).

answered Apr 26, 2019 at 12:26

Bloodmallet

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