Regex in php - preg_replace issues

Question

I would like to catch and replace a regex in a variable but I'm getting some troubles. The regex I'm trying to catch is a pattern like that :

one or many letters (one or many numbers (may have a .) one or many numbers) one or many letters

What I'm trying to do is to replace the whole string with only figures in it. Here's an example :

6Â Â° C => 6 1015.12 hPa => 1015.12 distance 172.1 km => 172.1

And here is my regex so far (don't blame me, I'm not really into regex haha) :

$test = preg_replace('#([a-zA-Z]*([0-9]*(\.)*[0-9]*)[a-zA-Z]*)#i', '$2', $myString);

Thanks in advance for you help !

so you only want to keep the numbers and letters where they belong? — Craig White
– Craig White, Commented Apr 8, 2011 at 9:30

Alfred · Accepted Answer · 2011-04-08 09:33:06Z

1

$result = preg_replace("/[^0-9,.]/","", $string);

answered Apr 8, 2011 at 9:33

Alfred

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3 Comments

Thank you !! I didn't think to think that way (delete everything which is not interessing) !

then close your question please

@alexbts, if this answer satisfied your needs you should accept it by activating the check mark on the left of this answer.

alexbts · Accepted Answer · 2011-04-08 09:36:25Z

0

Ok,

It seems I found the answer. My pattern wasn't correct, here's a good one :

'#[\D]([0-9](.)[0-9])[\D]*#i'

answered Apr 8, 2011 at 9:36

alexbts

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