MATLAB Use contains function within an IF statement

Question

I have a cell array, strings of months in MATLAB. I am using the contains() function to determine if 'Ju' is in the string, along with an if statement, and if the statement is true, then delete 'Ju.' But I am getting an error. The error is: Undefined function or variable 'a'.

Error in Untitled (line 4) if a == contains(months, pattern)

pattern = 'Ju';
months = {'June', 'July', 'August', 'September'};

if a == contains(months, pattern)
    a = regexprep(months, 'Ju', '')
end

What error are you getting?

scotty3785
– scotty3785

2019-05-01 15:26:19 +00:00
Commented May 1, 2019 at 15:26 — scotty3785
– scotty3785, Commented May 1, 2019 at 15:26

gnovice · Accepted Answer · 2019-05-01 15:27:05Z

2

For your example, you don't even need an if statement. regexprep can handle it all for you:

>> pattern = 'Ju';
>> months = {'June', 'July', 'August', 'September'};
>> a = regexprep(months, pattern, '')

a =

  1×4 cell array

    'ne'    'ly'    'August'    'September'

answered May 1, 2019 at 15:27

gnovice

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Comments

L. Scott Johnson · Accepted Answer · 2019-05-01 15:27:37Z

1

You need to set a before testing it:

>> a = contains(months, pattern)

a =

  1×4 logical array

  1   1   0   0

answered May 1, 2019 at 15:27

L. Scott Johnson

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