i have problem like this..
arr = [['1' '2' '']['3' '4' '']['5' '6' '']]
then, how do I delete the last element - array[n][2] I have tried and searching google a lot but didn't solve it please help me to solve this problem thank you...
arr = [['1' '2']['3' '4']['5' '6']]
Use numpy.delete(arr,-1,1)
arr = numpy.array([['1','2',''],['3','4',''],['5','6','']])
arr = numpy.delete(arr,-1,1)
The result will be:
[['1' '2']
['3' '4']
['5' '6']]
I would use a numpy.apply_along_axis to remove the last element from each sublist
import numpy as np
arr = np.array([['1', '2', ''],['3' ,'4', ''],['5', '6' ,'']])
#Slice each sublist to remove the last element using apply_along_axis
arr = np.apply_along_axis(lambda x: x[:-1], 1, arr)
print(arr)
The output will be
[['1' '2']
['3' '4']
['5' '6']]
numpy tag.
arr is just list. I think numpy is not mandatory if we can solve it in standard library.In [415]: arr = np.array([['1', '2', ''],['3' ,'4', ''],['5', '6' ,'']])
...:
In [416]: arr
Out[416]:
array([['1', '2', ''],
['3', '4', ''],
['5', '6', '']], dtype='<U1')
Just take a column slice:
In [417]: arr[:, :-1]
Out[417]:
array([['1', '2'],
['3', '4'],
['5', '6']], dtype='<U1')
This produces a new array, but that's normal with numpy. Most numpy actions, especially ones that change size/shape, do that.
The OP display of arr is consistent with it being numpy array. However for copy-n-paste the repr display is better.
In [418]: print(arr)
[['1' '2' '']
['3' '4' '']
['5' '6' '']]
I have an idea to check '' with len().
arr = [['1', '2', ''],['3', '4', ''],['5', '6', '']]
arr = [[a for a in ar if len(a) > 0] for ar in arr]
print (arr)
The result is:
[['1', '2'], ['3', '4'], ['5', '6']]
