Regex is not working in Golang HandleFunc function

Question

I am trying to redirect the URL based on a pattern in Go. If my URL is containing "clientApi" then I am sending it to clientApiPoint func otherwise I am sending it to redirectApiPoint func. My handleRequest func is

func handleRequest()  {
    r := mux.NewRouter()
    r.HandleFunc("/", homePage)
    r.HandleFunc("/clientApi", clientApiPoint)
    r.HandleFunc("/{^((?!clientApi).)*$}", redirectApiPoint)
    http.Handle("/", r)
    log.Fatal(http.ListenAndServe(":8081", nil))
}

{^((?!clientApi).)*$} regex is working fine if my url is something like

localhost:8081/somerandonurl  (sending it to redirectApiPoint func)

but if there one or more "/" in the url, regex is not redirecting it to redirectApiPoint func.

localhost:8081/somerandonurl/somethingdifferent    (not sending it to redirectApiPoint. 404 page not found message)

http.HandleFunc() can not be used to register a pattern to match a regular expression. — Roman Kiselenko
– Roman Kiselenko, Commented May 6, 2019 at 7:01
Are you taking the / into consideration? Also, you might not want to compile a regular expression every time the endpoint is hit - it's an expensive operation. Compile it elsewhere just once(if it won't change). — cbll
– cbll, Commented May 6, 2019 at 7:04

LinPy · Accepted Answer · 2019-05-06 07:02:29Z

1

your Regex work on "localhost:8081/somerandonurl" because of the first "/" so it matched.

you need somthing like "/(.*$)" but this will match any /blala/blala/...

you can test your regex from here: Regex

answered May 6, 2019 at 7:02

LinPy

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