How can I sort list of pairs using second key in python?

Question

I have a list of nested lists:

e = [['Tina', 37.2], ['Harsh', 39], ['Harry', 37.21], ['Berry', 37.21], ['Akriti', 41]]

How do you sort by numerical value, yet the names 'follow' the 'grade'? I could use dict, but I think it misses the point.

Mureinik · Accepted Answer · 2019-05-11 22:12:11Z

2

You could sort the list with a custom key:

result = sorted(e, key = lambda x : x[1])

answered May 11, 2019 at 22:12

Mureinik

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sanyassh · Accepted Answer · 2019-05-11 22:11:57Z

1

e.sort(key=lambda item: item[1])

answered May 11, 2019 at 22:11

sanyassh

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tonypdmtr · Accepted Answer · 2019-05-11 23:22:25Z

0

In your example Harry and Berry have the same value.

If you want ties to be sorted by name, a variation of the answers you got already would be something like this:

e = [['Tina', 37.2], ['Harsh', 39], ['Harry', 37.21], ['Berry', 37.21], ['Akriti', 41]]

e.sort(key=lambda x:(x[1], x[0]))

print(e)
#[['Tina', 37.2], ['Berry', 37.21], ['Harry', 37.21], ['Harsh', 39], ['Akriti', 41]]

edited May 11, 2019 at 23:22

answered May 11, 2019 at 22:20

tonypdmtr

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2 Comments

donkopotamus Over a year ago

Why not just the much simpler lambda x: (x[1], x[0])?

tonypdmtr Over a year ago

Only because I didn't think about it :) Will edit. Thanks.

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