hey i have this array
[
0: "Migration, MD"
1: "Lution, MD"
2: "Mover, MD"
3: "Dee"
4: "Prov10A"
]
how to get the value which has the word MD in it like which has MD it should give me something like this
[
0: "Migration, MD"
1: "Lution, MD"
2: "Mover, MD"
]
how can i do that with lodash? thanks
Use filter and includes:
const arr = ["Migration, MD", "Lution, MD", "Mover, MD", "Dee", "Prov10A"];
const res = arr.filter(e => e.includes("MD"));
console.log(res);.as-console-wrapper { max-height: 100% !important; top: auto; }
You can use filter, toLowerCase & includes. filter will return a new array, toLowerCase will convert the case of the element so both md ,MD will be considered.
let k = ["Migration", "MD", "Lution, MD", "Mover, MD", "Dee", "Prov10A"].filter(function(item) {
return item.toLowerCase().includes('md')
});
console.log(k)you can try the filter function
const arr = [
"Migration, MD", "Lution, MD" , "Mover, MD", "Dee", "Prov10A"
]
const out = arr.filter(e => e.includes('MD'))
console.log(out)
If you want to find only one word with "MD" or only the first one, you can use java script find method, and if you want an array of words having "MD" then you can use filter method.
const arr = [
"Migration, MD", "Lution, MD" , "Mover, MD", "Dee", "Prov10A"
]
const result = arr.find(word=>word.includes("MD"));
console.log(result);
// to get array of words with MD simply change .find as .filter in above code.
MDseparated by word boundaries (spaces, punctuation marks, etc.) ?