It's a bit like in_array but while in_array checks the presence of one element in an array and returns true and false accordingly, I want to know whether all elements of array1 is part of array2.
Ex:
$array1 = array(3, 30);
$array2 = array(5, 30);
$array3 = array(5, 50);
$array = array(50,7,8,456,1,5,567);
function new_in_array($array1,$array) // false
function new_in_array($array2,$array) // false
function new_in_array($array3,$array) // true
Any idea?
array_intersect will do:
<?php
$first = array('foo', 'bar');
$second = array('foo', 'bar','baz');
var_dump(array_intersect($first, $second) === $first); // True
$first = array('foo', 'bar', 'hello');
$second = array('foo', 'bar','baz');
var_dump(array_intersect($first, $second) === $first); // False
Use array_intersect to intersect those two and check the number of elements in the return array:
$intersect = array_intersect($array1, $array2);
if (count($intersect) == count($array1)) {
// array1 is fully contained in array2
}
Or use array_diff():
function array_contains($haystack, $needles) {
return !count(array_diff($needles, $haystack));
}
array_contains($array2, $array1); // all elements of array1 is part of array2?
You could also use a for loop.
for ($i = 0; $i < sizeof($array1); $i++) {
if (!in_array($array1[$i], $array2)) {
return False;
}
}
return True;
