I am using a JNI API (that i can't change) that return a fixed size char array that represent a string.
I am converting it to String with String.valueOf(char [])
The problem is that i can receive an array like this {'a','b','c','\0','\0','\0'}
Using valueOf() keeps the trailing NULLs and a I get a wrong string.
Is there a simple way to convert such and array to string and removing NULLs?
String s = String.valueOf(bits).trim();
just trim the string it'll get rid of all *leading & *trailing white space.
String.trim() removes all leading and trailing characters that are equal to or below the space (<= 0x20); that includes control characters.
Normally you would get both an array and a length variable that tells how many characters are to be read from the array. If you don't have length variable you can find it with a loop and use new String(char[], int, int) constructor:
char[] arr = {'a','b','c','\0','\0','\0'};
int len = 0;
do {
len++;
} while (arr.length > len && arr[len] != '\0');
String s = new String(arr, 0 ,len);
System.out.println(s); // abc
\0. And that there won't be any in middle.\0.I did it like this: Since the nulls are only at the end of the charArray, I went through the array backward and counted how many nulls it had. Then I iterated through the array using its length minus the number of nulls as the upper limit in the for next loop and built the final string without the trailing nulls.
Like this:
public String getStringFromBufferedCharArray(char[] cArray) {
StringBuilder finalString = new StringBuilder();
int count = 0;
for (int x = cArray.length - 1; x >= 0; x--) {
if ((int) cArray[x] == 0) count++;
else break;
}
int end = cArray.length - count;
for (int x = 0; x < end; x++) {
finalString.append(cArray[x]);
}
return finalString.toString();
}
