I currently have a pattern substitution that does the following:
x = re.sub('(\d+)','\g<1>','100')
=> x = 100
I need to be able to divide the integer by 10 in the substitution as the pattern and substitution are inputs from database text fields (so I can't use code). Is there a way to do this so that => x = 10
Thanks, Richard
import re
t = 'a b c 100 200'
f = lambda x: str(int(x.group(0)) / 10)
re.sub('\d+', f, t)
# returns 'a b c 10 20'
you can do this by passing a function as 2nd argument to re.sub. That function will be called with a MatchObject :
>>> def repl(mo):
... return mo.group(0)[:-1]
...
>>> import re
>>> re.sub('\d+', repl, '100')
'10'
re.sub can take function as a second parameter.
import re
def func(r):
return str(int(r.group(0)) / 10)
x = re.sub("\d+", func, "100")
print x
