How to extract a subString from android java String?

Question

I tried to extract Sub-String from java string, but failed. i tried like this

String text = "audios/{any_number} any_audio_name.mp3";
text= text.substring(text.indexOf('/'), text.indexOf('3')-2);

Updated

I need String contains only any_audio_name and removing audios/ , any number e.g. {123} and .mp3

For example audios/{211} new school poem.mp3 to new school poem

If you don't want to include the /, use text.indexOf('/')+1. And better to use lastIndexOf('.') than relying on subtracting 2. — Andy Turner
– Andy Turner, Commented May 29, 2019 at 19:18
If you're working with file names, Apache Commons has FileNameUtils that do the hard work for you and would scale better. — Compass
– Compass, Commented May 29, 2019 at 19:19
Regex is overkill ... anyway, duplicate stackoverflow.com/questions/924394/… — second
– second, Commented May 29, 2019 at 19:42

Malinda · Accepted Answer · 2019-05-29 19:41:14Z

1

This answer might helpful

String text = "audios/any_audio_name.mp3";
text= text.substring(text.indexOf('/')+1, text.indexOf('.'));

answered May 29, 2019 at 19:41

Malinda

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4 Comments

Attaullah Over a year ago

this also work but previous one give me answer first

Andreas Over a year ago

You'd probably want to use lastIndexOf for both of them. Whether changing that or not, you should also cross your fingers and hope to never see input like foo.bar/file_without_extension

Malinda Over a year ago

Yes you correct but in here his requirement is to get name of mp3 file.so most probably that file come with .mp3 extention and he describe file path as audios

Attaullah Over a year ago

Actually i read XML data is in server in listview, first i filtered (whole line into name) and then showing it in listview.

Qingfei Yuan · Accepted Answer · 2019-05-29 20:06:13Z

1

Use regex seems fit here.

public class MyMain{
    public static void main(String args[]) {
        String line = "audios/any_audio_name.mp3";
        String pattern = "audios\\/(.*)\\.mp3";

        // Create a Pattern object
        Pattern r = Pattern.compile(pattern);

        // Now create matcher object.
        Matcher m = r.matcher(line);

        if (m.find()) {
            System.out.println("Found value: " + m.group(1));
        } else {
            System.out.println("NO MATCH");
        }
    }
}

edited May 29, 2019 at 20:06

answered May 29, 2019 at 19:21

Qingfei Yuan

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8 Comments

Paul Lemarchand Over a year ago

"^.*/(.*)\\..*$" would fit more cases. You can't use \/, it's either \\/ or /. And use group(1).

Attaullah Over a year ago

String pattern = "audios\/(.*).mp3"; give "Illegal escape character in string literal" error

Attaullah Over a year ago

I/System.out: NO MATCH

Andreas Over a year ago

Simpler to just use replace, e.g. text = text.replaceFirst("^(?:.*?/)?([^/]+?)(?:\\.[^./]*?)?$", "$1"); --- See demo on regex101

Andreas Over a year ago

@Attaullah 1) Learn regex. 2) Update the pattern in the replace call.

|

Malinda · Accepted Answer · 2019-05-29 20:19:12Z

1

For Your Edited Question.Following Code segment will help you but here i assume that there will be no number within "any_audio_name"

String text = "audios/{any_number}any_audio_name.mp3";
text= text.substring(text.indexOf('/')+1, text.indexOf('.')).replaceAll("[\\d.]", "");;

answered May 29, 2019 at 20:19

Malinda

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2 Comments

Attaullah Over a year ago

but {} is remaining

Attaullah Over a year ago

.replaceAll("\\{|\\}|[\\d.]",""); is use this

Attaullah · Accepted Answer · 2019-05-29 20:40:54Z

0

Thanks for everyone, who give me idea for solving this issue.

 String text = "audios/{any_number}any_audio_name.mp3";
 text= text.substring(text.indexOf('/')+1, text.indexOf('.')).replaceAll("\\{|\\}|[\\d.]","");
 System.out.println(text);

answered May 29, 2019 at 20:40

Attaullah

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