How to format json response in php before echoing it out in js file

Question

$ch = curl_init($url);
$result = curl_exec($ch);

this is the result

{"response":"1", "name":"john", "id":22, "again":0, "text":xe};

Before echoing it in the js file via ajax I want to format it so I only get the data which i want to use which is id and name but its outputting the wrog data

$data = array();
$data[] = array("id"=>$result.'id', "name"=>$result.'name');
echo $data;

data it prints

( [0] => Array ( [id] => 1id and so on

See this answer. You won't need the loop but it should give you an idea of how to achieve what you want. — Matt Stannett
– Matt Stannett, Commented Jun 2, 2019 at 9:06

saeed_m · Accepted Answer · 2019-06-02 09:16:20Z

0

if you want result become an object do below

$obj = json_decode($result);

if you want resualt become an array do below

$arr = json_decode($result , true);

echo $obj->name;
echo $arr['name'];

answered Jun 2, 2019 at 9:16

saeed_m

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2 Comments

venabeo Over a year ago

For some reason '$arr = json_decode($result , true);' After than echoing arr gives the output 1 print_r($arr); Same thing happens when i use $obj = json_decode($result);

saeed_m Over a year ago

what you want to echo should be as this -->echo $arr['name'];

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