how do I loop through an array assign a variable to each item in Objective C

Question

I have an array that contains 16 items

NSArray *centreFreqValues = @[@250, @750, @1250, @1750, @2250, @2750, @3250, @3750, @4250, @5250, @5750, @6250, @6750, @7250, @7750];

I have a loop that performs various tasks:

for (int i = 0; i < 16; i++) {
//do some other stuff
int centreFreq = centreFreqValues[i];
NSLog(@" here is each integer %d", centreFreq);

}

but I'm getting the error message:

Incompatible pointer to integer conversion initializing 'int' with an expression of type 'id'

These are NSNumber instances, not int. So you can either use %@ instead of %d. Or you can get the intValue as Sandy described. — Rob
– Rob, Commented Jun 3, 2019 at 7:30

Tharindu Ketipearachchi · Accepted Answer · 2019-06-04 07:15:31Z

4

Try this. This way is easy.

NSArray *centreFreqValues = @[@250, @750, @1250, @1750, @2250, @2750, @3250, @3750, @4250, @5250, @5750, @6250, @6750, @7250, @7750];

for (id value in centreFreqValues) {

    NSLog(@" here is each integer %d", [value integerValue]);
}

answered Jun 4, 2019 at 7:15

Tharindu Ketipearachchi

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Comments

Sanoj Kashyap · Accepted Answer · 2019-06-03 07:16:31Z

0

Either You need to declare an array of integers or while assigning typecast to int.

[centreFreqValues[i] intValue] just check

edited Jun 3, 2019 at 7:16

answered Jun 3, 2019 at 7:01

Sanoj Kashyap

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2 Comments

VK1 Over a year ago

so..NSInteger centreValues = [16]?

rmaddy Over a year ago

This answer is misleading. In Objective-C you can't create an array of integers (not directly) and you can't do this via typecasting.

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