I have an array of objects with the following format. Each object has got few properties and also an array. I have to fetch a property if a key is present in the array.
Consider the below object: When I give key as 7 it should return me 'xyz'. If key is 3 it should give me 'abc'
[
{
val : 'abc',
arr : [1,2,3,4]
},
{
val: 'xyz',
arr : [7,8,9]
}
]
You can use find() and includes(). Use find of the main array and check if the arr of that object includes() the given key. return the val property of the found object.
const arr = [
{
val : 'abc',
arr : [1,2,3,4]
},
{
val: 'xyz',
arr : [7,8,9]
}
]
const getVal = (arr,key) => (arr.find(x => x.arr.includes(key)) || {}).val;
console.log(getVal(arr,3))
console.log(getVal(arr,7))You can use Array.filter() to filter the object which meets the condition whereby the element (7) exists in the array. Within the callback function for Array.some(), you can use Array.includes() to check if the element (7), exists in the arr property itself:
const data = [
{
val : 'abc',
arr : [1,2,3,4]
},
{
val: 'xyz',
arr : [7,8,9]
}
]
const res = data.filter(obj => obj.arr.includes(7))[0].val;
console.log(res);
arr of any object will not contain the given key.
[0].val should be on a separate statement, and should only run if the array isn't empty?filter()[0] in a variable and then use ternary operator to return a value. Or either use || {}. Like (data.filter(obj => obj.arr.includes(7))[0] || {}).valYou can try this too.
var x = [{
val: 'abc',
arr: [1, 2, 3, 4]
},
{
val: 'xyz',
arr: [7, 8, 9]
}
];
var test = function(data, key) {
for (let i of x) {
if (i.arr.indexOf(key) >= 0)
return i.val;
}
}
// example
console.log(test(x,9));
for (i of x) here you are declaring a global variable. Use let before i. And also answers like try this are not encouraged you should explain what you are doing in code.
arrcontains 7 as well?