validate string with regex on android

Question

I want that my string didn't contain *,; and $. I use this code

private static boolean IsMatch(String s, String pattern) {
         try {
             Pattern patt = Pattern.compile(pattern);
             Matcher matcher = patt.matcher(s);
             return matcher.matches();
         } catch (RuntimeException e) {
           return false;
         }  
}



String regex ="[^*;$]";
System.out.println(IsMatch(url,regex));

But this method return always false. Can any one tell me what's the problem

WhiteFang34 · Accepted Answer · 2011-04-13 08:46:31Z

4

Try using [^*;$]* for your regex. It'll return true if your string doesn't contain any of *, ; and $. I'm assuming you want your regex to match strings that don't contain any of those characters since you're already using ^ inside [ and ].

edited Apr 13, 2011 at 8:46

answered Apr 13, 2011 at 8:30

WhiteFang34

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1 Comment

WhiteFang34 Over a year ago

@foufi: this returns true for me with your method: System.out.println(IsMatch("http://example.com", "[^*;$]*"));

Thomas · Accepted Answer · 2011-04-13 08:47:47Z

2

Try this regex [^\\*;\\$]*. * and $ are special characters in regex.

Edit: If you're using Pattern you should use this regex: String regex = "^[^\\*;\\$]*$", since you want to match the whole string.

As an alternative you could just use url.matches("[^\\*;\\$]*"); where you don't need the first ^ and last $, since that method tries to match the whole string anyways.

edited Apr 13, 2011 at 8:47

answered Apr 13, 2011 at 8:30

Thomas

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Thomas Over a year ago

True, I took ^ as a character, not the negation. Fixed that.

user684934 · Accepted Answer · 2011-04-13 08:33:10Z

0

You need to take out ^ and $, because they can occur anywhere in your string.

String regex = "[\*,;\$]";

Note the backslash escaping the $ symbol. Edit: and the * symbol.

answered Apr 13, 2011 at 8:33

user684934

Comments

Josnidhin · Accepted Answer · 2011-04-13 08:40:01Z

0

You will need to escape some of the characters like this [\^*;\$]

answered Apr 13, 2011 at 8:40

Josnidhin

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