How to get multiple regex on same string in scala

Question

My requirement is to get multiple regex patterns in a given String.

"<a href=\"https://page1.google.com/ab-cd/ABCDEF\”>Hello</a> hiiii <a href=\"https://page2.yahoo.com/gr\”>page</a><img src=\"https://image01.google.com/gr/content/attachment/987654321\” alt=\”demo image\”></a><a href=\"https://page3.google.com/hr\">"

With this below code:

val p = Pattern.compile("href=\"(.*?)\"")
    val m = p.matcher(str)
    while(m.find()){
      println(m.group(1))
    }

I am getting output:

https://page1.google.com/ab-cd/ABCDEF
https://page2.yahoo.com/gr
https://page3.google.com/hr

With change in Pattern:

val p = Pattern.compile("img src=\"(.*?)\"")

I am getting output:

https://image01.google.com/gr/content/attachment/987654321

But with Pattern:

val p = Pattern.compile("href=\"(.*?)\"|img src=\"(.*?)\"")

I am getting output:

https://page1.google.com/ab-cd/ABCDEF
https://page2.yahoo.com/gr
Null
https://page3.google.com/hr

Please let me know, how to get multiple regex pattern or is their any other easy way to do this?

Thanks

Wiktor Stribiżew · Accepted Answer · 2019-06-06 09:37:31Z

1

You may use

val rx = "(?:href|img src)=\"(.*?)\"".r
val results = rx.findAllMatchIn(s).map(_ group 1)
// println(results.mkString(", ")) prints:
//  https://page1.google.com/ab-cd/ABCDEF, 
//  https://page2.yahoo.com/gr, 
//  https://image01.google.com/gr/content/attachment/987654321, 
//  https://page3.google.com/hr

See the Scala demo

Details

(?:href|img src)=\"(.*?)\" matches either href or img src, then a =", and then captures any 0+ chars other than line break chars as few as possible into Group 1, and then a " is matched
With .findAllIn, you get all matches, then .map(_ group 1) only fetches Group 1 values.

edited Jun 6, 2019 at 9:37

answered Jun 6, 2019 at 8:54

Wiktor Stribiżew

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