I am getting an array of values and I want to send them to a predefined function with the same parameter count.
The naive way is to do:
values = [1,2,3,4] # getting it from outside
if len(values) == 1:
func(values[0])
elif len(values) == 2:
func(values[0], values[1])
.
.
.
is there more elegant way ?
You can use arbitrary argument lists
def func(*args):
for arg in args:
print(arg)
values = [1]
func(*values)
values = [1, 2]
func(*values)
func(1)
func(1,2)
The output will be
1
1
2
Or just pass the entire array to the function via func(values)
def func(values):
for value in values:
print(value)
values = [1]
func(values)
values = [1, 2]
func(values)
func(values).
func(a) till func(a,b,c,d) ? well you would need some kind of conditional to identify how many arguments are being passed, or you would need an intermediate functions which can do that for you @asaf You can't really avoid this where number of arguments are variable
func(values)?