Convert jQuery object into PHP array using HTML form

Question

I have a jQuery object which is appended to form field like,

var params = {
    'product_id': productId,
    'width': width,
    'drop': drop
};

$("#sample-form input[name='params']").val(params);

Form looks like,

<form id="sample-form" action="url" method="post">
    <input type="hidden" name="params"/>
    <button type="submit">Submit</button>
</form>

On receiving this "params" using POST data in PHP, I get string with value "[object Object]"

How do I convert this into array?

You could use JSON. ...val(JSON.stringify(params)). Then deserialise that value when sent to your PHP — Rory McCrossan
– Rory McCrossan, Commented Jun 24, 2019 at 13:32
Store it as stringified json val(JSON.stringify(params));. Then in PHP, you do: $params = json_decode($_POST['params'], true); to get it as a PHP array. — M. Eriksson
– M. Eriksson, Commented Jun 24, 2019 at 13:38

Vinoth Kumar · Accepted Answer · 2019-06-24 13:47:48Z

1

I converted jQuery object into stringified JSON as,

$("#sample-form input[name='params']").val(JSON.stringify(params));

In PHP, convert received JSON into PHP array as,

$params = json_decode($_POST['params'], true);

answered Jun 24, 2019 at 13:47

Vinoth Kumar

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