How to remove specific String stored in an ArrayList

Question

I have a code which stores the values for later use. But I need to find the exact names and not the whole. I am getting output like below:

Output result shows: [ Ranjit Nayak ( Attorney ), ranjti Nyak ( Case Manager ), shenoy attorney ( Parallegal ) ]

So I need to use some method to remove content including brackets. Please help.

In the code: CaseManagersreceivingreminders is a global ArrayList, I have a similar another ArrayList stored values. Once the string is edited successfully I need to compare both the array values.

Tried trim, replace. Nothing works.

    List<WebElement> PMPageCMList =
        driver.findElements(By.xpath("//div[@id='collapseCM']/div[2]/div[2]/div"));

    int totalcms = PMPageCMList.size();
    for (int i = 1; i <= totalcms; i++) {
        CaseManagersreceivingreminders.add(
            driver
                .findElement(By.xpath("//div[@id='collapseCM']/div[2]/div[2]/div" + "[" + i + "]" + "/span"))
                .getText()
        );
    }

    Collections.sort(CaseManagersreceivingreminders);
    Collections.sort(ReminderCMsList);

    try {
        boolean isEqual = CaseManagersreceivingreminders.contains(ReminderCMsList);
        System.out.println(isEqual);
        Log.pass("Data matching" + isEqual);
    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

I should get the output like: [ Ranjit Nayak, ranjti Nyak, shenoy attorney ]

then you have to walk through each element of the array and replace the element with the modified one. Where is the problem now? Or just create a new array based on the new elements, doesn't matter here for small arrays — UninformedUser
– UninformedUser, Commented Jun 27, 2019 at 12:10
How can split() and trim() related to Selenium? Am I missing something? — undetected Selenium
– undetected Selenium, Commented Jun 27, 2019 at 13:10
You should stick to the Java Naming Conventions: variable names are always written in camelCase. — MC Emperor
– MC Emperor, Commented Jun 27, 2019 at 22:00

Hulya · Accepted Answer · 2019-06-27 14:33:45Z

1

You can use regex to remove (...) part of the String:

List<String> newList =  new ArrayList<>();

for(String s: CaseManagersreceivingreminders) {
    s = s.replaceAll("\\(.*\\)", "");
    newList.add(s);
}

System.out.println(newList);

Output:

[Ranjit Nayak, ranjti Nyak, shenoy attorney]

About \\(.*\\) regex:

\\( and \\) : For any special characters like ( or ) you should use \\ before them to match.
.* : Matches any character zero or more times.

Thus \\(.*\\) expression can match part of a string like ( Attorney )

edited Jun 27, 2019 at 14:33

answered Jun 27, 2019 at 14:09

Hulya

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Comments

Dmitriy Popov · Accepted Answer · 2019-06-27 13:01:57Z

0

Your Collection CaseManagersreceivingreminders is a list of strings, so just iterate over the list, for each string split over '(' and save the new strings in a new list.

for (String names : CaseManagersreceivingreminders) {
    CaseManagersreceivingreminders_New.add(names.split("(")[0]);
}

edited Jun 27, 2019 at 13:01

Dmitriy Popov

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answered Jun 27, 2019 at 12:13

RohanJ

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2 Comments

Ranjit Over a year ago

but this will only remove 1st (, how about the content inside the bracket?

RohanJ Over a year ago

@ranjitnayak "Ranjit Nayak ( Attorney )".split("(") will split the string into two strings "Ranjit Nayak " and " Attorney )" . Read more about split() method here -docs.oracle.com/javase/7/docs/api/java/lang/…

Bohemian · Accepted Answer · 2019-06-27 14:16:25Z

0

Use the replaceAll() method of List, with a suitable UnaryOperator:

list.replaceAll(s -> s.replaceAll(" *[(].+?[)]", ""));

answered Jun 27, 2019 at 14:16

Bohemian♦

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Comments

Samuel Philipp · Accepted Answer · 2019-06-27 21:43:39Z

0

You can remove the (...) part from each string using the following regex: \s*\(.*\)

If you want to update the existing list you can use List.replaceAll():

Pattern pattern = Pattern.compile("\\s*\\(.*\\)");
list.replaceAll(s -> pattern.matcher(s).replaceAll(""));

Alternatively you can use Java Streams if you want to create a new list with the results:

Pattern pattern = Pattern.compile("\\s*\\(.*\\)");
List<String> result = list.stream()
        .map(s -> pattern.matcher(s).replaceAll(""))
        .collect(Collectors.toList());

answered Jun 27, 2019 at 21:43

Samuel Philipp

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