How to wait for a async function while running via shell in nodejs

Question

I have a file

demo.js

with a function that waits for fetch data from DB like this

exports.findNames = async () => {
  const names= await Student.find();
  console.log('Names:', names);
  return names;
};

So, while I testing this function via the shell/command line, which not waiting for the function to be completed.

Tested like this

node ./demo findNames

NB: Student is a model, response sending from another file that's why not here. and it's not a middleware. Mongoose used as db tool

its a simple nodejs file for getting students details from db using mongoose. — Shibin Raju Mathew
– Shibin Raju Mathew, Commented Jun 27, 2019 at 18:10

Aritra Chakraborty · Accepted Answer · 2019-06-27 18:36:01Z

1

You need to await or .then the function in your demo.js. Let me give you an example:

names.js

exports.findNames = async () => {
    const names= await new Promise((res,rej)=>{
        setTimeout(()=>{
            res([1,2,3])
        }, 100);
    });
    console.log('Names:', names);
};

demo.js

const name = require('./names');
(async ()=>{
    await name.findNames();
})();

Output

$ node demo.js
Names: [ 1, 2, 3 ]

edited Jun 27, 2019 at 18:36

answered Jun 27, 2019 at 18:10

Aritra Chakraborty

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4 Comments

Aritra Chakraborty Over a year ago

There is a problem with your demo.js code. Please post it here, because this example works.

Shibin Raju Mathew Over a year ago

Updated code with relevant info. res sending from another file that's why not here. and it's not a middleware.

Aritra Chakraborty Over a year ago

You need to have a driver function like my demo.js to call your findNames function

Alex Kuzmin Over a year ago

It never returns.

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