How to let each array index have a struct instance

Question

I have a 2-dimensional 5x5 array in Swift. I am trying to have each array item to present a struct that has properties like cost and heuristics. for example, the grid[0][0] item should have cost and heuristics values.

Swift implementation:

struct Spot {
    var cost: Int  // cost
    var heu: Int  // heuristics
}

var grid = [[Int]]

In Javascript I used to do it as:

function Spot() {
  this.cost = 0;
  this.heu = 0;
}

//This is what I'm looking for something equivalent in Swift
grid[0][0] = new Spot();

Sorry if this seems very basic, but I'm a beginner in Swift.

Depending on what exactly Spot is (its name, and the names of its members don't really communicate much), you probably want an [[Int?]], with nils marking the empty spots, rather than Spot instances with 0 cost and 0 "heu" — Alexander
– Alexander, Commented Jul 6, 2019 at 1:45

Leo Dabus · Accepted Answer · 2019-07-05 22:15:18Z

3

You need an array of Spot arrays [[Spot]], not an array of Int arrays [[Int]].

struct Spot {
    let cost: Int  // cost
    let heu: Int  // heuristics
}

var grid: [[Spot]] = .init(repeating: .init(repeating: .init(cost: 0, heu: 0), count: 5), count: 5)

grid[0][0] = .init(cost: 10, heu: 5)

print(grid)  // "[[Spot(cost: 10, heu: 5),...
print(grid[0][0].cost)   // 10
print(grid[0][0].heu)    // 5

answered Jul 5, 2019 at 22:15

Leo Dabus

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