Convert comma separated String into Json string

Question

String input = "Vish,Path,123456789";

Expected output as Json string, and thread safe = {"name":"Vish","surname":"Path","mobile":"123456789"}

I tried by using

 GsonBuilder gsonBuilder = new GsonBuilder(); 
 Gson gson = gsonBuilder.create();

But every time I'm creating new Object -

MappingObject[] studentArray = new MappingObject[1]; 
studentArray[0] = new MappingObject("Vish","Path","123456789");

I separated this comma separated string by using split()

 System.out.println("JSON "+gson.toJson(studentArray));

@sidgate I tried by using GsonBuilder gsonBuilder = new GsonBuilder(); Gson gson = gsonBuilder.create(); But every time I'm creating new Object - MappingObject[] studentArray = new MappingObject[1]; studentArray[0] = new MappingObject("Vish","Path","123456789"); I separated this comma separated string by using split() System.out.println("JSON "+gson.toJson(studentArray)); So, I want to create single object only even if I work with multiple student and that conversion process should be thread safe as well. — vishal pathode
– vishal pathode, Commented Jul 9, 2019 at 6:47
Use JSONObject constructor with Map<String,String> as argument — halfpad
– halfpad, Commented Jul 9, 2019 at 6:51

halfpad · Accepted Answer · 2019-07-09 06:47:17Z

1

You will have to create a Map:

Map<String,String> jsonMap = new HashMap<String,String>();
jsonMap.put("name","Vish");
jsonMap.put("surname","Path");
jsonMap.put("mobile","123456789");

Then use com.google.gson JSONObject: JSONObject jsonObj = new JSONObject(jsonMap);

answered Jul 9, 2019 at 6:47

halfpad

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Comments

Mathias G. · Accepted Answer · 2019-07-09 06:59:09Z

If you don't want to use any library then you have to split string by comma and make a new String.

String input = "Vish,Path,123456789";
String[] values=input.split("[,]");
StringBuffer json = new StringBuffer();// StringBuffer is Thread Safe
json.append("{")
    .append("\"name\": \"").append(values[0]).append("\",")
    .append("\"surname\": \"").append(values[1]).append("\",")
    .append("\"mobile\": \"").append(values[2]).append("\"")
    .append("}");
System.out.println(json.toString());

Output :

{"name": "Vish","surname": "Path","mobile": "123456789"}

If you want to use library then you will achive this by Jackson. Simple make a class and make json by it.

public class Person {
  private String name;
  private String surname;
  private String mobile;

  // ... getters and Setters
}

String input = "Vish,Path,123456789";
String[] values=input.split("[,]");
Person person = new Person(values[0],values[1],values[2]);// Assume you have All Argumets Constructor in specified order  
ObjectMapper mapper = new ObjectMapper(); //com.fasterxml.jackson.databind.ObjectMapper;
String json = mapper.writeValueAsString(person);

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