I have a string which looks like this :
'< 5s' or '< 0.5s'
And i'm trying to extract the 'duration' from the string. I already have this :
a = '< 5s'
b = int(list(filter(str.isdigit, a))[0])
print(b)
but if i use '< 0.5s' it returns me 0. How can i include the , with the number ?
With simple regex:
import re
s = '< 0.5s'
dur = re.search(r'-?\d+(\.\d+)?', s).group()
print(dur) # 0.5
import re
b = re.sub("[^\d\.]", "", a)
A simple b = float(a[2:-1]) should do the trick, if you are certain that the string is always formatted exactly as shown in your example.
You can use regex, maybe something like this:
#!/usr/bin/python3
import re
inp="< 0.5s 5s -12z34 -6.7s"
for i in re.findall("-?\d+\.\d+|-?\d+", inp):
print(i)
