How to parse json value without keys using RestTemplate?

Question

I want to parse json value but there are some value without keys.

like this

"geometry": {
                "type": "LineString",
                "coordinates": [
                    [
                        127.08373748622218,
                        37.529508099979225
                    ],
                    [
                        127.08355138558433,
                        37.529735847943925
                    ]
                ]
            }

Geometry.class

@Getter
@NoArgsConstructor(access = AccessLevel.PROTECTED)
@ToString
public class Geometry {
    private String type;
    private Coordinate coordinates;
}

Coordinate.class

@Getter
@NoArgsConstructor(access = AccessLevel.PROTECTED)
@ToString
public class Coordinate {
    private List<Double[]> xy;
}

then i saw this error

Caused by: com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of `kr.seoulmaas.ieye.service.dto.path.walk.Coordinate` out of START_ARRAY token
 at [Source: (PushbackInputStream); line: 1, column: 133] (through reference chain: kr.seoulmaas.ieye.service.dto.path.WalkPathResDto["features"]->java.util.ArrayList[0]->kr.seoulmaas.ieye.service.dto.path.walk.Feature["geometry"]->kr.seoulmaas.ieye.service.dto.path.walk.Geometry["coordinates"])

Post a complete minimal example, with hardcoded JSON input, trying to deserialize this JSON input. — JB Nizet
– JB Nizet, Commented Jul 14, 2019 at 10:00

devgianlu · Accepted Answer · 2019-07-14 10:18:32Z

1

private Coordinate coordinates; should be private List<Coordinate> coordinates; since it is an array in the JSON, but since the array contains only arrays you need to have a list of lists: List<List<Double>> coordinates (suggested by @JBNizet).

edited Jul 14, 2019 at 10:18

answered Jul 14, 2019 at 10:11

devgianlu

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1 Comment

JB Nizet Over a year ago

It should actually be a List<List<Double>>, or a List<Double[]> directly. It' not an object, but it's also not an array of objects.

user404 · Accepted Answer · 2019-07-14 10:48:29Z

0

In your data, coordinates is a list of list. So define your Geometry class this way:

@Getter
@NoArgsConstructor(access = AccessLevel.PROTECTED)
@ToString
public class Geometry {
    private String type;
    private List<Coordinate> coordinates;
}

Hope this helps.

answered Jul 14, 2019 at 10:48

user404

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Comments

Bebop · Accepted Answer · 2019-09-04 02:10:03Z

0

Sorry, I'm dreadfully late.

I solved this problem using by JsonNode.

this is my code.

public class Geometry {
    private String type;
    private JsonNode coordinates;
}

edited Sep 4, 2019 at 2:10

answered Sep 3, 2019 at 1:17

Bebop

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2 Comments

Jake Over a year ago

But how did you solve it by using JsonArray? It may not be as clear to some as to how you did it. Please update your answer with more details, thanks!

Bebop Over a year ago

Oh, Sorry i confused with JsonNode. I solve this problem with JsonNode.

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