How to find a substring after a string in a file and increment that number using sed/awk in shell scipting?

Question

I have a abc.toml file having following content :

[env]
    APPLICATION_NAME = 'loy'
    COMPONENT_NAME = 'web-loy'
    AAAS_VERSION='0.0.2'
    AAAS_FLAVOR='apache-base'
    CONF_VERSION='0.0.1'
    SERVICE_VERSION='0.0.2'

I want to write a script in shell so that I can call it and increment the version no. in CONF_VERSION. i.e After calling script, CONF_VERSION should become '0.0.2', and next time '0.0.3' and so on...

Expected output after calling the script once is:

[env]
    APPLICATION_NAME = 'loy'
    COMPONENT_NAME = 'web-loy'
    AAAS_VERSION='0.0.2'
    AAAS_FLAVOR='apache-base'
    CONF_VERSION='0.0.2'
    SERVICE_VERSION='0.0.2'

Jotne · Accepted Answer · 2019-07-15 07:12:03Z

1

This will increment the last digit for CONF_VERSION

awk '/CONF_VERSION/ {split($2,a,".");++a[3];$0=$1FS a[1]"."a[2]"."a[3]FS}1' FS="'" file
[env]
    APPLICATION_NAME = 'loy'
    COMPONENT_NAME = 'web-loy'
    AAAS_VERSION='0.0.2'
    AAAS_FLAVOR='apache-base'
    CONF_VERSION='0.0.2'
    SERVICE_VERSION='0.0.2'

PS you do not write what should happen after 0.0.9. This awk gives 0.0.10

Edit:

awk '/CONF_VERSION/ {split($2,a,".");if (a[3]==9) {a[3]=0;++a[2]} else {++a[3]};$0=$1FS a[1]"."a[2]"."a[3]FS}1' FS="'" file

This version will change from 0.0.9 to 0.1.0 and not 0.0.10

edited Jul 15, 2019 at 7:12

answered Jul 15, 2019 at 6:53

Jotne

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2 Comments

Harshit Goel Over a year ago

The output right now is : CONF_VERSION='0.0.2 What should be edited to get output as CONF_VERSION='0.0.2'

Jotne Over a year ago

@HarshitGoel You can do this awk 'code' abc.toml > tmp && mv tmp abc.toml

John1024 · Accepted Answer · 2019-07-15 07:38:34Z

1

Here is another awk version:

$ awk -F'[.]' '/CONF_VERSION=/{$3=($3+1)"\x27"} 1' OFS=. abc.toml
[env]
    APPLICATION_NAME = 'loy'
    COMPONENT_NAME = 'web-loy'
    AAAS_VERSION='0.0.2'
    AAAS_FLAVOR='apache-base'
    CONF_VERSION='0.0.2'
    SERVICE_VERSION='0.0.2'

How it works

-F'[.]'

This tells awk to use . as the field separator for input.
/CONF_VERSION=/{$3=($3+1)"\x27"}

This selects only lines which contain CONF_VERSION=. For those lines, the third field is incremented by 1 and a single quote is appended.

\x27 means a single quote. It is expressed this way so as not to confuse the shell.
1

This tells awk to print the line.
OFS=.

This tells awk to use a period as the field separator for output.

To update in-place

If you have GNU awk (sometimes called gawk), use:

gawk -i inplace -F'[.]' '/CONF_VERSION=/{$3=($3+1)"\x27"} 1' OFS=. abc.toml

The following will update in place regardless of the awk version:

awk -F'[.]' '/CONF_VERSION=/{$3=($3+1)"\x27"} 1' OFS=. abc.toml >temp && mv temp abc.toml

edited Jul 15, 2019 at 7:38

answered Jul 15, 2019 at 7:06

John1024

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8 Comments

Harshit Goel Over a year ago

To update the file abc.toml also I am using :awk -F'[.]' '/CONF_VERSION=/{$3=($3+1)"\x27"} 1' OFS=. abc.toml > abc.toml But it is not working. How can I update the file also and not printing on console?

John1024 Over a year ago

@HarshitGoel I just added to the end of the answer two methods for updating the file instead of printing on the console.

Harshit Goel Over a year ago

After running this, I am getting an out put like this: Usage: awk [POSIX or GNU style options] -f progfile [--] file ... Usage: awk [POSIX or GNU style options] [--] 'program' file ... POSIX options: GNU long options: (standard) -f progfile --file=progfile gawk is a pattern scanning and processing language. By default it reads standard input and writes standard output.

John1024 Over a year ago

@HarshitGoel Oops. I had a typo in the second version. Try the corrected version awk -F'[.]' '/CONF_VERSION=/{$3=($3+1)"\x27"} 1' OFS=. abc.toml >temp && mv temp

Harshit Goel Over a year ago

Thanks @John1024 That really helped :)

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