Capturing error message of curl in BASH script andchecking status

Question

I need 4 things from curl in a BASH script:

I need to capture brief humanly readable error message from curl into a bash variable.
I need to be able to check that the command completed successfully or not.
I need the command to run
I don't want anything printed to console unless I echo it.

m=$(curl -u "$user":AP"$pass" -T "$pathA" "$url")
if [ $? -ne 0 ] ; then
   echo "Error: ""$m"
fi

The problem is curl puts gibberish into $m. It just dumps the error to console instead of m. I don't want anything printed to console unless I echo it. And I only want to capture error descriptions. I tried many variations, nothing seemed to work for this use-case... at least nothing suggested here on Stack.

You are using command substitution to capture ALL output from curl in m except you are not capturing stderr. Add 2>&1 at the end of your curl command, e.g. ..."$url" 2>&1) Also echo "Error: $m" is sufficient. — David C. Rankin
– David C. Rankin, Commented Jul 20, 2019 at 0:37
That's right -- you should make that an answer so it can be marked correct. — GaryO
– GaryO, Commented Jul 20, 2019 at 0:41

oaccamsrazor · Accepted Answer · 2019-07-20 00:41:22Z

4

curl sends errors to STDERR and will not get captured by $m. The output of curl is sent to STDERR (that gibberish you mentioned).

One solution is to redirect STDERR to STDOUT by adding 2>&1 to your curl invocation in your script:

m=$(curl -u "$user":AP"$pass" -T "$pathA" "$url" 2>&1)
if [ $? -ne 0 ] ; then
   echo "Error: ""$m"
fi

You could also use the --fail, --silent and --show-errors flags of curl like in this example if all you care about are the errors:

Making curl send errors to stderr and everything else to stdout

and some information about capturing STDERR to $variable in bash scripts:

Bash how do you capture stderr to a variable?

answered Jul 20, 2019 at 0:41

oaccamsrazor

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Eric Aya · Accepted Answer · 2022-11-09 14:15:23Z

0

Similar to one suggested; I m just using the output stderror as $? is always 0.

OUTPUT=$(curl -X POST -H 'Content-type: application/json' --data "{\"text\":\"$MSG \"}" $SLACK_URL 2>1)
echo $OUTPUT
if [[ $OUTPUT == "ok" ]]; then
  echo "$FILE_NAME Msg successfully sent"
elif [[ $OUTPUT == "invalid_token" ]]; then
  echo "$FILE_NAME Slack url incorrect"
else
  echo "$FILE_NAME Some issue Sending msg"
fi

edited Nov 9, 2022 at 14:15

Eric Aya

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answered Nov 9, 2022 at 13:06

Its not blank

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