I have array like
var arr = ['8888', '2222|1', '6666', '4444|2']
and I need get index of item which include first number (before |if symbol exists). Below is helpful RegExp, you can use it, works.
var result = new RegExp('\\b' + value.replace(/^(.*)\|.*$/, '$1') + '\\b').test(arr);
value = '2222'; \\true
value = '222'; \\false
value = '2222|1'; \\false
but I need index, not if item exists.
value = '8888'; \\0
value = '2222'; \\1
value = '222'; \\-1
value = '2222|1'; \\-1
Use findIndex
var arr = ['8888', '2222|1', '6666', '4444|2']
const getIndex = (arr, n) => arr.findIndex(a => a.split("|")[0] === n);
console.log(getIndex(arr, "8888"))
console.log(getIndex(arr, "2222"))
console.log(getIndex(arr, "222"))
console.log(getIndex(arr, "2222|1"))If findIndex is not supported, you could add this polyfill to make
the method available in Array.prototype. You could also use a simple for loop and return when a match is found:
var arr = ['8888', '2222|1', '6666', '4444|2']
function getIndex(arr, n) {
for (var i = 0; i < arr.length; i++) {
if (arr[i].split("|")[0] === n)
return i;
}
return -1;
}
console.log(getIndex(arr, "8888"))
console.log(getIndex(arr, "2222"))
console.log(getIndex(arr, "222"))
console.log(getIndex(arr, "2222|1"))Another option suggested by T.J. Crowder:
var index = -1;
arr.some(function(a, i) {
if (a.split("|")[0] === n) {
index = i;
return true;
}
});
var index = -1; arr.some(function(a, i) { if (a.split("|")[0] === n) { index = i; return true; }); some is ES5.
@t you get suggested the name and you can select it. You can only mention on handle in comment. Since you already @ me, T.J's name won' show up in autofilll