How to display some of the JSON Data in select option using php?

Question

I connect to an API and receive a JSON Data with PHP. After execute:

$countries= curl_exec($ch);
$jd_countries = json_decode($countries, TRUE);
print $countries;

The result of this is:

I would like to use for each to add the country_id and name to option value

So my code will be something like this:

<select name="country" class="form-control" >
    <?php foreach($jd_countries as $value){ ?>
        <option value="<?php echo $country_id;?>"><?php echo $name;?>
        </option> 
    <?php } ?>
</select>

I receive this:

Notice: Array to string conversion in C:\xampp\htdocs\account\index.php on line 28 Array

Notice: Array to string conversion in C:\xampp\htdocs\account\index.php on line 28 Array

Any suggestions? Thanks in advance.

What is $jd_countries ? And you never use $value, what is $country_id and $name ? — Mickaël Leger
– Mickaël Leger, Commented Jul 24, 2019 at 9:27

Denis · Accepted Answer · 2019-07-24 09:37:40Z

3

<?php foreach($jd_countries['data'] as $country){ ?>
   <option value="<?php echo $country['country_id'];?>"><?php echo $country['name'];?>
   </option>
<?php } ?>

edited Jul 24, 2019 at 9:37

answered Jul 24, 2019 at 9:26

Denis

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2 Comments

Antonis Over a year ago

Hi Denis. Thanks for your answer. I change my code and I receive this error: Notice: Trying to get property of non-object in C:\xampp\htdocs\account\index.php on line 27 Warning: Invalid argument supplied for foreach() in C:\xampp\htdocs\account\index.php on line 27

Denis Over a year ago

hey yes, sorry I was trying to take the data like $jd_countries->data but it's an array not object so change it to $jd_countries['data']. I also have changed the answer

Somnath Rokade · Accepted Answer · 2019-07-24 09:37:16Z

0

You need to convert $countries to array

$jd_countries= json_decode($countries, TRUE);

<?php foreach($jd_countries->data as $country){ ?>
   <option value="<?php echo $country['country_id'];?>"><?php echo $country['name'];?>
   </option>
<?php } ?>

answered Jul 24, 2019 at 9:37

Somnath Rokade

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