I have to match multiple lines in python.
group one start
line 1 data
group end
group two start
group two data
group end
on the above string how to get below output
[group one start \n line 1 data \n group end, group two start \n group two data \n group end]
I have tried below code but not working
import re
re.findall(r'group.*start.*group end',re.MULTILINE | re.DOTALL)
for info in data:
print info
Maybe, an expression somewhat similar to:
\bgroup [\s\S]*? start\b[\s\S]*?\bgroup end\b
or:
\bgroup .*? start\b.*?\bgroup end\b
with a DOTALL flag might be working here.
DOTALL:import re
regex = r"\bgroup .*? start\b.*?\bgroup end\b"
test_str = """
group one start
line 1 data
group end
group two start
group two data
group end
"""
print(re.findall(regex, test_str, re.DOTALL))
DOTALL:import re
regex = r"(\bgroup [\s\S]*? start\b[\s\S]*?\bgroup end\b)"
test_str = """
group one start
line 1 data
group end
group two start
group two data
group end
"""
print(re.findall(regex, test_str))
['group one start\nline 1 data\ngroup end', 'group two start\ngroup two data\ngroup end']
The expression is explained on the top right panel of regex101.com, if you wish to explore/simplify/modify it, and in this link, you can watch how it would match against some sample inputs, if you like.
You can just split the text based on the pattern group end, but without capturing it using a look-behind
>>> import re
>>> text_data = """group one start
... line 1 data
... group end
... group two start
... group two data
... group end"""
>>>
>>> re.split(r'(?<=group end)\n', text_data)
['group one start\nline 1 data\ngroup end', 'group two start\ngroup two data\ngroup end']
Below code working for me
a = """group one start
line 1 data
group end
group two start
group two data
group end
"""
all_m = re.findall(r'group.*?start.*?group end',a,re.DOTALL)
for m in all_m:
print(m)
print("**********")
Output
group one start
line 1 data
group end
*************
group two start
group two data
group end
*************