PHP in_array returning wrong value

Question

Here is the one value that can not determine PHP in_array function. I think this is issue with value but why ? I am stuck.

"ZQjEa8EsL2kdHr2xD2jkoWj678FWsLL2Ng1tFjDV/Rgkt0CLiE4f+lvlYrdDjvq2"

PHP Example

<?php
    $id = "ZQjEa8EsL2kdHr2xD2jkoWj678FWsLL2Ng1tFjDV/Rgkt0CLiE4f+lvlYrdDjvq2";
    $array['selected_options']['12251_12754_3'][0] = 0;

    var_dump(in_array($id, $array['selected_options']['12251_12754_3']));
?>

Output

true

Try it online!

Question : Anybody knows why this happen or what I do instead ?

Answers much appriciated !

heck you can even do var_dump(in_array(null, $array['selected_options']['12251_12754_3'])); and it'll still yield true — Kevin
– Kevin, Commented Jul 29, 2019 at 7:40
You are searching a string variable in int array declare array as string or id as int try again — Cafer Yükseloğlu
– Cafer Yükseloğlu, Commented Jul 29, 2019 at 7:41

mighty_dev · Accepted Answer · 2019-07-29 07:45:10Z

2

Searches for needle in haystack using loose comparison unless strict is set.

Append the third argument with true to get the result you need.

var_dump(in_array($id, $array['selected_options']['12251_12754_3'], true));

See documentation.

edited Jul 29, 2019 at 7:45

mighty_dev

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answered Jul 29, 2019 at 7:40

Markus Zeller

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1 Comment

Cafer Yükseloğlu Over a year ago

Isn't that gonna always throw false ?

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