getting a list of string placeholders using java stream

Question

I have a string with a number of place holders, is there any way if we can collect all the place holders in one go with the help of java streams?

Input:

<Html>
 <Table>
  <TR><TD>||BuySell||</TD></TR>
  <TR><TD>||ExchangeName||</TD></TR>
 </Table>
</Html>

Output:

List<String> placeholders = [BuySell,ExchangeName]

@Sweeper, Thanks for your reply. No it is a string. I have broken down the fixed html templates to different sub templates of Strings. — user11620797
– user11620797, Commented Aug 4, 2019 at 4:28
Have you? The input you showed here seems to me like a HTML string though, not a "different sub templates of Strings", whatever that means. Can you clarify? — Sweeper
– Sweeper, Commented Aug 4, 2019 at 4:34
@Sweepr, Thanks for your patience. What I meant is the input is a String. — user11620797
– user11620797, Commented Aug 4, 2019 at 4:40
Yes, I know the input is a String now, but is it HTML? If so, you should use an HTML parser. Are you using an HTML parser? — Sweeper
– Sweeper, Commented Aug 4, 2019 at 4:42

Ranjeet · Accepted Answer · 2019-08-06 06:16:11Z

0

This can be done using a helper function.

    BiFunction<Matcher, Function<Matcher, Object>, Collection<?>> placeHolderExtractor = (mch, extracter) -> {
        List<Object> list = new ArrayList<>();
        while(mch.find()) {
            list.add(extracter.apply(mch));
        }

        return list;
    };

    String htmlStr = "<Html> <Table>  <TR><TD>||BuySell||</TD></TR>  <TR><TD>||ExchangeName||</TD></TR> </Table></Html>";
    String regex = "(\\|\\|)([\\w]+)\\1";

    Pattern pattern = Pattern.compile(regex);
    Matcher matcher =  pattern.matcher(htmlStr);

    List<String> placeHolderList = placeHolderExtractor.apply(matcher, macher -> macher.group(2))
    .stream()
    .map(String::valueOf)
    .collect(Collectors.toList());

answered Aug 6, 2019 at 6:16

Ranjeet

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