separating out the array in javascript

Question

I am going through an object and separating out the array in customer and customerportals but my code is not working

var j=0;
var k = 0;
var myVar[j][k] = Array();

$.each(Object.customer, function(index, value) { 

    $.each(value.portal.customerPortal, function(innerIndex, innerValue) { 

        myVar[j][k] = innerValue.name;
            k++;

        });
        j++;
    });

    alert(myVar[0][0]);

any help would be great

Did you really assign a customer property to Object? Also don't use Array(), use []. — Ry-
– Ry- ♦, Commented Apr 20, 2011 at 23:50

Quentin · Accepted Answer · 2011-04-20 23:52:35Z

2

JavaScript is not Java. The syntax to declare an array is: someVariable = []

So:

var j=0;
var k = 0;
var myVar = [];
myVar[j] = [];

Which creates an array, containing one element at index 0 (which is another array)

answered Apr 20, 2011 at 23:52

Quentin

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4 Comments

Asim Zaidi Over a year ago

how do i make it 2 dimenssional? I am confused

Asim Zaidi Over a year ago

I guess I am trying to find how to get the values of myvar[j][k] out then and use them

Lightness Races in Orbit Over a year ago

@Autolycus: You don't. Javascript is not typed in that manner. You just add arrays as elements.

user166390 Over a year ago

@Autolycus ([['foo'],['bar']])[1][0] -> "bar" Note that it is one operator [index], applied twice, to two different objects (the array containing the two arrays, and then the array containing 'bar'), just like in Java (neither Javascript nor Java have true n-dimensional arrays).

Lightness Races in Orbit · Accepted Answer · 2011-04-21 00:00:04Z

1

Your array declaration syntax is wrong (even, C-like!).

var myVar = [];

$.each(Object.customer, function(index, value) { 

    var newElm = [];
    $.each(value.portal.customerPortal, function(innerIndex, innerValue) { 
        newElm.push(innerValue.name);
    });

    myVar.push(newElm);
});

alert(myVar[0][0]);

answered Apr 21, 2011 at 0:00

Lightness Races in Orbit

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