Python3 subprocess.check_output catch exception without printing

Question

I'm working on using subprocess.check_output to call ping command and get some output. The script will catch the wrong domain name. However, the output of the ping command will always print out on its own. When there's no exception, the output will not print out on its own.

hostname = "somewrongdomain.com"  # This domain will not connect
try:
    response = (subprocess.check_output(["ping", "-c 1", self.hostname]).decode("utf-8")
    print(response)

except subprocess.TimeoutExpired as e:
    ping_rating = 0

except subprocess.CalledProcessError as e:
    ping_rating = 0

#do something else

The output I'm getting:

$ python3 test.py
ping: sendto: No route to host

Is there any way to NOT print the output(ping: sendto: No route to host) when the exception is caught?

ShadowRanger · Accepted Answer · 2019-08-08 07:16:10Z

2

As written in the documentation subprocess.check_output only captures STDOUT.

To also capture standard error in the result, use stderr=subprocess.STDOUT:

>>> subprocess.check_output(
...     "ls non_existent_file; exit 0",
...     stderr=subprocess.STDOUT,
...     shell=True)
'ls: non_existent_file: No such file or directory\n'

edited Aug 8, 2019 at 7:16

ShadowRanger

158k12 gold badges221 silver badges314 bronze badges

answered Aug 8, 2019 at 7:14

krase

1,0447 silver badges18 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Python3 subprocess.check_output catch exception without printing

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related