I use a variable to save an ip like this, but I need to verify that it really has an ip format. The ip field does not always have to be a list. I have this:
ip=["8.8.8.8","8.8.8.6"] # List or only one element
reg_ip = r'(?:\d{1,3}\.)+(?:\d{1,3})'
filter_ip=re.findall(reg_ip,ip)
But the answer is as follows
filter_ip= [u"8.8.8.8",u"8.8.8.6"]
And therefore does not meet the condition
if ip == reg_ip:
How should I do it?
import re
ip="8.8.8.8"
reg_ip = r'(?:\d{1,3}\.)+(?:\d{1,3})'
filter_ip=re.findall(reg_ip,ip)
if ip in reg_ip:
pass
Basically, you are checking if there any matches with Regex, so .findall will return you the number of matches
import re
ip=["8.8.8.8","8.8.8.6"]
reg_ip = re.compile(r'(?:\d{1,3}\.)+(?:\d{1,3})')
filter_ip = list(filter(reg_ip.search, ip))
if ip == filter_ip:
print "All ip Matched!"
Recommend you to use .search if you have a single ip to check for as its faster and you need not need multiple matches.
Using .search
ip="8.8.8.8"
reg_ip = r'(?:\d{1,3}\.)+(?:\d{1,3})'
if re.search(reg_ip,ip):
print "Matched !"
re.search()?