How to keep specific key-value element in array and remove rest?

Question

$array_one

Array (
    [2018] => Array ()

    [2019] => Array
        (
            [5] => 2966
        )

    [2020] => Array
        (
            [0] => 2930
            [1] => 2919
        )
)

2nd array is :

$costs

I want to only keep those records in my 2nd array which are in 1st array and I want to unset remaining records from 2nd array

How to keep only those records in 2nds array which match the key values in 1st array?

Just use a couple of foreach loops and check the indexes match, if not use unset() — Shardj
– Shardj, Commented Aug 12, 2019 at 9:21

Nick · Accepted Answer · 2019-08-12 09:24:40Z

1

This is a looping version of the code in this answer:

$output = array();
foreach ($array_one as $key => $keys) {
    if (count($keys))
        $output[$key] = array_intersect_key($costs[$key], array_flip($keys));
}
print_r($output);

Output:

Array
(
    [2019] => Array
        (
            [2966] => Array
                (
                    [jh] => 0
                    [presta] => 0
                    [log] => 0
                )
        )
    [2020] => Array
        (
            [2930] => Array
                (
                    [jh] => 0
                    [presta] => 0
                    [log] => 0
                )    
            [2919] => Array
                (
                    [jh] => 0
                    [presta] => 0
                    [log] => 0
                )    
        )    
)

Demo on 3v4l.org

answered Aug 12, 2019 at 9:24

Nick

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Comments

Rahul · Accepted Answer · 2019-08-12 09:36:27Z

0

You can use array_intersect_key,

foreach($costs as $k => &$val) // & to save value to value itself
{
    if(!empty($array_one[$k])){
        $val = array_intersect_key($val, $array_one[$k]);
    }
}

This will reduce no of iterations,

$result=[];
foreach ($array_one as $k => $val) {
    if (!empty($val))
        $result[$k] = array_intersect_key($costs[$k], array_flip($val));
}
print_r($result);

Ultimately, it will only keep only those index's data which is matching with array_one

edited Aug 12, 2019 at 9:36

answered Aug 12, 2019 at 9:21

Rahul

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