How to get the next item in an array using for (let obj of objects) [duplicate]

The loop does not offer any syntax to do this, but you can combine the destructuring syntax introduced in ES6 with calling the entries() method on the array:

for (const [i, v] of ['a', 'b', 'c'].entries()) {
  console.log(i, v)
}

Here is the best example you can refer

let list = [4, 5, 6];

for (let i in list) {
    console.log(i); // "0", "1", "2",
}

for (let i of list) {
    console.log(i); // "4", "5", "6"
}

Use in to get the index:

for (let index in list) {
  // Use index
}

Or use forEach:

list.forEach((item, index) => {...});

A simple solution would be to iterate the keys of the list via for(..in..) and, per-iteration, add one to the current index to obtain the index of the next value from the current iteration like so:

let list = [4, 5, 6];

for (let i in list) {

  const next = list[Number.parseInt(i) + 1];

  console.log('curr=', list[i]);
  console.log('next=', next);
  console.log('---');
}

Some points to consider with this are:

• the last next value will be undefined
• this approach only works for arrays where values are accessed via integer indices
• the index of i needs to be parsed to an interger to ensure that the "add one" step returns the index of the next value (rather than a string concatenation)