How I can get average number from array without using array_sum or any other function?

Question

I had a task to write program that gives 20 numbers from 9 to 99 using empty array and rand function which I did...but the second step is for me to calculate and get the average number.

With functions like array_sum I can get what I want, but the idea is not to use any of array functions, just arithmetic operators

$arrNums = array();
$sum = 0;
$intTotalNum = 20;

for($i = 0; $i < $intTotalNum; $i++) {
  $intRand = rand(9, 99);
  $arrNums[] = $intRand;
  $sum = $sum + $arrNums;
  $average = $sum / count($arrNums);
}


var_dump($arrNums);
echo "<br>";
echo $average;

Code gives me an error "Unsupported operand types"

you are trying add a integer with an array that's why the error "Unsupported operand types" — sh1hab
– sh1hab, Commented Aug 22, 2019 at 10:38

Jaymin · Accepted Answer · 2019-08-22 10:44:06Z

2

This is how you can achieve it without using an array functions:

$arrNums = array();
$sum = 0;
$intTotalNum = 20;

for($i = 0; $i < $intTotalNum; $i++) 
{
  $intRand = rand(9, 99);
  array_push($arrNums,$intRand);
  $sum = $sum+$intRand;
}


echo '<pre>';
print_r($arrNums);
echo "<br>";
echo $sum;


//echo $average;

Just add your $sum to current $intRand and print it outside the loop.

The reason why I have used array_push functions so that you can print all the array elements outside for loop and check and verify how many numbers generated. If you don't want to print an array then it is no need, you can comment or remove it.

edited Aug 22, 2019 at 10:44

answered Aug 22, 2019 at 10:42

Jaymin

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2 Comments

sh1hab Over a year ago

array_push is a array function !

Jaymin Over a year ago

Updated! I have just used to push elements for debugging purpose, I am not manipulating any array functions to get sum :) @shihab

Jmel Becha · Accepted Answer · 2019-08-22 10:51:36Z

1

Just put the $average out side the for loop


    $arrNums = array();
    $sum = 0;
    $intTotalNum = 20;

    for($i = 0; $i < $intTotalNum; $i++) {
      $intRand = rand(9, 99);
      $arrNums[] = $intRand;
      $sum += $intRand;

    }

    $average = $sum / $intTotalNum;

    var_dump($arrNums);
    echo "<br>";
    echo $average;

answered Aug 22, 2019 at 10:51

Jmel Becha

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Comments

sh1hab · Accepted Answer · 2019-08-22 11:53:07Z

0

You are trying add a integer with an array that's why the error "Unsupported operand types" . you can get the average more easily like this



    $sum = 0;
    $intTotalNum = 20;
    $arrNums = array();

    for($i = 0; $i < $intTotalNum; $i++) {
      $arrNums[] = rand(9, 99);
      $sum = $sum + $arrNums[$i];
    }

    $average = $sum / $intTotalNum;
    var_dump($arrNums);
    echo "<br>";
    echo $average;

edited Aug 22, 2019 at 11:53

answered Aug 22, 2019 at 10:42

sh1hab

6715 silver badges16 bronze badges

4 Comments

Developer123 Over a year ago

Can you explain me why we need variable $intSum with value of 0, and how that affects on code to give us average number?

sh1hab Over a year ago

we are initializing $sum with 0 so that we can add other values into it . like it is a basket before you put anything on it you have to empty it . so that it remains with only the things that you have put into it

Andreas Over a year ago

It's a complete waste to calculate the average on each iteration.

sh1hab Over a year ago

@Andreas you are right .i have updated my code . At first i just pointed the fault in his code

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