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lst = ["g1 act car", "a8 act zoo", "a2 act car"]

I want to sort a list such that:

  1. Ignoring 1st token of each string, strings are ordered lexicographically
  2. If there's a tie, order as per the 1st token

Above list after sorting should be as follows:

lst = ["a2 act car", "g1 act car", "a8 act zoo"]

I want to write the sorting code in a single line. I can write the code for the 1st condition as follows:

lst = sorted(lst, key = lambda x : x.split()[1])

How can I combine the second condition as well in this lambda expression?

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3 Answers 3

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2

Try using:

lst = sorted(lst, key = lambda x : (x.split(None, 1)[1], x.split()[0]))

And now:

print(lst)

Is:

['a2 act car', 'g1 act car', 'a8 act zoo']
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Comments

1

I would do it following way:

lst = ["g1 act car","a8 act zoo","a2 act car"]
lst = sorted(lst, key=lambda x:x.split(None,1)[::-1])
print(lst)

Output:

['a2 act car', 'g1 act car', 'a8 act zoo']

Explanation: x.split(None,1) cut at first space (or other seperator), so I get list with 1st token and rest, then I reverse them, so [rest, 1st token] are used as key, therefore it sorts by rest and then 1st token in case same rest appear more than once.

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Comments

0

Try using:

lst = sorted(lst, key = lambda x : [x.split()[1:], x.split()[0]])

And now:

lst

The result as follow:

['a2 act car', 'g1 act car', 'a8 act zoo']
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