Adding variable containing string to array does not work

Question

Being very new to bash and unix I'm once again struggling with a very basic issue, i.e. adding a string to an array. What I'm trying to achieve, is to have an array of file names matching a certain pattern. Here's my script:

declare -a TASKS=()
find /cs/srpresul/app/deploy/config/imas-config/rdx-tasks-prepared/ -name 
"IMAS-Loaders-*.json"|while read fname; do
   FILE_NAME=$(echo $fname | cut -d'/' -f11)
   echo "$FILE_NAME"
   TASKS+=("$FILE_NAME")
done
TASKS+=('foo' 'bar')
for TASK in "${TASKS[@]}"
do
   echo "$TASK"
   echo "Starting back population for type $TASK between $1 and $2"
done

So the result is as follows: the FILE_NAME variable holds proper value, as it is printed correctly, but the TASKS array does not contain them. Only 'foo' and 'bar' values are present in the array. Any ideas what am I doing wrong?

mik1904 · Accepted Answer · 2019-08-27 09:12:29Z

3

You are using a pipe so you are appending to TASKS in a subshell that is why it does not work. You can use the following:

declare -a TASKS=()
for fname in $(find /cs/srpresul/app/deploy/config/imas-config/rdx-tasks-prepared/ -name 
"IMAS-Loaders-*.json"); do
   FILE_NAME=$(echo $fname | cut -d'/' -f11)
   echo "$FILE_NAME"
   TASKS+=("$FILE_NAME")
done
TASKS+=('foo' 'bar')
for TASK in "${TASKS[@]}"
do
   echo "$TASK"
   echo "Starting back population for type $TASK between $1 and $2"
done

edited Aug 27, 2019 at 9:12

answered Aug 27, 2019 at 8:59

mik1904

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