can I use a function that is outside the current function?
eg.
function one($test){
return 1;
}
function two($id){
one($id);
}
Seems like i cant, how should I do it then to use the function that are outside? Thanks
The function is in the same file.. /
Is your function inside of a class? In that case you have to use $this->function() instead of function().
Your code looks valid to me : you are declaring two functions, called one and two ; and two is calling one.
Then, you can call any of those functions, to execute it.
For example, if you execute the following portion of code :
function one($test){
var_dump(__FUNCTION__);
return 1;
}
function two($id){
var_dump(__FUNCTION__);
one($id);
}
two('plop');
Note that I called two, in the last line of this example.
You'll get this kind of output :
string 'two' (length=3)
string 'one' (length=3)
Which shows that both functions were executed.
That works fine. However, one ignores its parameter. Then, two ignores the return value from one.
This should work fine Example:
<?php
function test ($asd)
{
return $asd;
}
function run ()
{
return test('dd');
}
echo run();
?>
Maybe you have an issue elsewhere?
two(5)would not produce any output, so you cannot know whether it "worked" or not. In any case, have a look at: php.net/manual/en/language.functions.php