Cannot Click Element with Selenium - element is either "not interactable" or "unable to locate"

Question

I am having a very difficult time clicking on the "Sign In" element at www.tradingview.com. I've inserted an implicitly_wait and have tried finding the element by xPath and class name. Regardless of what I try, I either get element not interactable or unable to locate element.

from selenium import webdriver

def sign_in():
    driver = webdriver.Chrome()
    driver.get('https://www.tradingview.com/')
    driver.implicitly_wait(10)
    driver.find_element_by_class_name('tv-header__profile-menu js-device-menu-btn').click()

sign_in()

@Emma unfort their API doesn't do what I need.

BorangeOrange1337
– BorangeOrange1337

2019-09-01 23:40:39 +00:00
Commented Sep 1, 2019 at 23:40 — BorangeOrange1337
– BorangeOrange1337, Commented Sep 1, 2019 at 23:40

Spencer Melo · Accepted Answer · 2019-09-01 23:54:38Z

2

Seems that you are trying to find the wrong element...

Try this one:

driver.find_element_by_xpath("//a[text()='Sign In']/ancestor::span").click()

edited Sep 1, 2019 at 23:54

answered Sep 1, 2019 at 23:35

Spencer Melo

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4 Comments

BorangeOrange1337 Over a year ago

I'm still getting the same unable to locate element error. Did that work for you?

Spencer Melo Over a year ago

@BorangeOrange1337 this page has some duplicated elements, try this one: driver.find_element_by_xpath("//a[text()='Sign In']/ancestor::span").click(), sorry for the first answer, I did not test it properly, this one was tested and clicked.

BorangeOrange1337 Over a year ago

TYVM, really appreciate the help. I don't understand tho, how did you find this? Shouldn't inspecting the sign-in button work?

Spencer Melo Over a year ago

Hi @BorangeOrange1337, after some analysis on the html, you can see that we have duplicated elements, basically, it has two versions, one for mobile and other one for PC, on this page you have two 'Sign In' buttons, your locator was finding the mobile version that you cannot interact if you are not on the mobile version, if you shrink or browser or change it to mobile version, your old locator probably will work.

QHarr · Accepted Answer · 2019-09-01 23:50:36Z

1

There are two sign ins. Target the second

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

def sign_in():
    driver = webdriver.Chrome()
    driver.get('https://www.tradingview.com/')
    WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.CSS_SELECTOR, '.tv-header__dropdown-text [href*=signin]'))).click()
sign_in()

If all else fails you can use javascript to click

driver.execute_script("document.querySelector('[href*=signin]').click();")

answered Sep 1, 2019 at 23:50

QHarr

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Comments

frianH · Accepted Answer · 2019-09-02 06:50:07Z

0

Hey try this once it will work

driver.findElement(By.Xpath("//span//a[text()='Sign In']")).click();

edited Sep 2, 2019 at 6:50

frianH

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answered Sep 2, 2019 at 4:03

Aditya Teja Gaddam

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Comments

Dmitri T · Accepted Answer · 2019-09-03 10:48:05Z

0

If you change the locator strategy to XPath Selector your code will be more readable and understandable
Consider using Explicit Wait as it's more flexible solution which saves time and CPU cycles.

Example code:

driver.get("https://www.tradingview.com/")
WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.XPATH, "//a[text()='Sign In']"))).click()

answered Sep 3, 2019 at 10:48

Dmitri T

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