Chrome console returning undefined when output is expected

b is the KEY of the window object, window[b] is the value. The key will always be a string.

for(var b in window) { 
   if(typeof(window[b]) == "function") console.log(b);}

for(var b in window) { 

Here, you're iterating through keys, not properties of the object. typeof of those keys is string, hence the condition under the if will never be fulfilled. And the undefined you get printed in the console is the value of the for statement (which is undefined).

Do instead

for(var b in window) { 
   if(typeof(window[b]) == "function") console.log(window[b]);}

b is the propery name (string), not the function itself. Try like this:

for(var b in window){
    if(typeof window[b]=='function') console.log(b)
}

The b variable ever is the type string, change left side condition to obtain function of window.

typeof(b)         // return string
typeof(window[b]) // return function

So the answer is this:

for(var b in window) { 
    if(typeof(window[b]) === "function") 
    {
        console.log(b);
    }
}

If we consider your code, 'typeof(b) == "function" ' it will never check this condition because typeof(b) is always a string.

The basic syntax to get a "string" key is obj["stringFormatKey"]. So here is the solution.

for(var b in window) { 
if(typeof(window[b]) == "function") console.log(b);}