How do i parse this string in javascript

Question

this url

"?route=system/template/update&template_id=22&token=200bfaa1f5d6cda4c782f98b15f32e7f"

and i just need the token out of it

 200bfaa1f5d6cda4c782f98b15f32e7f

how is the best way to parse that out...it seems to always be last

As you can see many of the answers vary their approach and some may not fit if the URL is even slightly different, this is mainly because the answers are referring to this specific case and no other variants since they don't know about them, if this is the only possible "form" you could encounter the URL, this is fine, but if you may have &otherthing=123 at the end, some may not work, maybe a clarification would help. — Trufa
– Trufa, Commented Apr 25, 2011 at 14:17
your right i noticed that there maybe another get var at the end...so i went with this input.match(/token=(\w+)/)[1] — Matt Elhotiby
– Matt Elhotiby, Commented Apr 25, 2011 at 14:21

brianpeiris · Accepted Answer · 2011-04-25 14:12:31Z

2

This should do it:

var
  input = "?route=system/template/update&template_id=22&token=200bfaa1f5d6cda4c782f98b15f32e7f",
  output = input.split("=").splice(-1)[0]; // output === "200bfaa1f5d6cda4c782f98b15f32e7f"

Or, if you're not sure that the token is always the last value:

var 
  input = "?route=system/template/update&template_id=22&token=200bfaa1f5d6cda4c782f98b15f32e7f&foo=bar&baz=spam",
  output = input.substring(input.indexOf('token=')).split(/[=&]/)[1]; // output === "200bfaa1f5d6cda4c782f98b15f32e7f"

edited Apr 25, 2011 at 14:12

answered Apr 25, 2011 at 14:06

brianpeiris

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1 Comment

g19fanatic Over a year ago

works great esp since the token is always last. Other wise this will not work.

Matt Elhotiby · Accepted Answer · 2011-04-25 14:16:09Z

1

Or use regular expression. In this case it will be like

Format

var re = /token\=(\S+)/i;
alert(url.match(re)[1]);

edited Apr 25, 2011 at 14:16

Matt Elhotiby

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answered Apr 25, 2011 at 14:07

Jakub Míšek

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1 Comment

Billy Moon Over a year ago

or... alert(input.match(/token=(\w+)/)[1])

Vlad Khomich · Accepted Answer · 2011-04-25 14:08:45Z

0

You can just replace the other part:

s = "?route=system/template/update&template_id=22&token=200bfaa1f5d6cda4c782f98b15f32e7f"

s.replace(/.*token=/, '')

#=> "200bfaa1f5d6cda4c782f98b15f32e7f"

answered Apr 25, 2011 at 14:08

Vlad Khomich

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Comments

Jim Blackler · Accepted Answer · 2011-04-25 14:09:22Z

0

s = "?route=system/template/update&template_id=22&token=200bfaa1f5d6cda4c782f98b15f32e7f";
s.match("[0-9a-z]*$");

Displays "200bfaa1f5d6cda4c782f98b15f32e7f"

answered Apr 25, 2011 at 14:09

Jim Blackler

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