JS objects equality

Question

I am trying to play with objects alongside with Symbol.toPrimitive symbol in order to convert objects to primitives.

I used this code:

function UserEq(name) {
    this.name = name;
    this[Symbol.toPrimitive] = function (hint) {
        alert("hint is: " + hint);
        return 0;
    };
}
function objectEqualityCheck() {
    let user1 = new UserEq("John");
    let user2 = new UserEq("Rambo");

    if (user1 == user2) alert("Equal!");
}

And I expect two conversions resulting in alert Equal!, but that is not what's hapenning...

When used like user1 == 0 all works fine (conversion is to number though).

Why when two objects are compared, it does not work?

EDIT: it doesn't work with === as well.

Because they are two different objects in two different spaces in memory. They are not the same object in the same allocated memory space, so by default object comparison, they are not equal — Taplar
– Taplar, Commented Sep 4, 2019 at 18:21
@Taplar Oh, I thought that == operator would make implicit conversion. — Michał Turczyn
– Michał Turczyn, Commented Sep 4, 2019 at 18:21
conversion occurs when you try to match two different type not when they are of same type — Code Maniac
– Code Maniac, Commented Sep 4, 2019 at 18:21
check this developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… — Arup Rakshit
– Arup Rakshit, Commented Sep 4, 2019 at 18:22
Possible duplicate of How to determine equality for two JavaScript objects? — VLAZ
– VLAZ, Commented Sep 4, 2019 at 18:24

Code Maniac · Accepted Answer · 2019-09-04 18:33:25Z

2

The first rule in the docs for == defines this

The comparison x == y, where x and y are values, produces true or false. Such a comparison is performed as follows:
If Type(x) is the same as Type(y), then
    Return the result of performing Strict Equality Comparison x === y.

TC39

user1 == user2

Here you're comparing same type so there's no type conversion happens at all

ToPrimitive is called only under these conditions

If Type(x) is either String, Number, or Symbol and Type(y) is Object, return the result of the comparison x == ToPrimitive(y).
If Type(x) is Object and Type(y) is either String, Number, or Symbol, return the result of the comparison ToPrimitive(x) == y.

edited Sep 4, 2019 at 18:33

answered Sep 4, 2019 at 18:27

Code Maniac

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