Why does this integer overflow occur?

Question

I've wrapped a dll method that has an integer as an out parameter in a web service. In testing I was finding that when I was expecting -1 I was getting 65,535 instead. I realised that the dll was using 16 bit integers and I was specifying the standard .NET 32bit integer when referencing the external dll in my code. this was quickly fixed by specifying a 16 bit integer and all is well.

My question is why did this happen? I could understand an overflow occuring if I was trying to fit a 32 bit integer in a 16 bit integer but I am not so sure why this happens the other way round. Clearly my understanding of this type of casting between types is a little lacking so any guidance will be greatly appreciated.

Paul Tomblin · Accepted Answer · 2009-02-23 15:30:31Z

6

A 16 bit integer "-1" has all 16 bits set. If you set the bottom 16 bits of a 32 bit integer, the value is 65,535. For an explanation of the internal representation of negative ints, have a look at this article.

answered Feb 23, 2009 at 15:30

Paul Tomblin

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Andy Rose Over a year ago

@Paul - Thanks for the explanantion and the link. Together they explained it nicely.

Jason Cohen · Accepted Answer · 2009-02-23 15:31:35Z

2

This happened because of the type-casting.

You don't actually send 16-bit integers on the call stack -- they're still 32-bit. So what the DLL returned exactly was:

0x0000ffff

If you cast this to e.g. sint16, this is -1, but if this is 32-bits, this is 65535.

answered Feb 23, 2009 at 15:31

Jason Cohen

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