I want to know the below code is correct or not
class A
{
public :
int show (int x, int y);
};
class B : public A
{
public :
float show (int a, int b); // can i overload this function ?
};
the show function is present in both base and derived class with different written types. I know function overloading concept (can not overload with different return types).
Is this possible to do so?
The code will be compiled successfully. The method A::show will not be overloaded but hidden.
You can call this method with the scope operator.
Class A
{
Public :
virtual int show (int x, inty) = 0;
};
class B:Public A
{
Public :
float show (int x, int y);
};
If you create a derived class object like
1)
B b;
b.show();
OR
2)
A* b = new B();
b->show();
Will always look into derived class, and call B::show().
This is for your particular example, where no virtual functions are present, if virtual functions are present in the base class, the second case can give different results in other cases, but in this particular example even base class virtual functions will make no difference.
