I would like to change the value of a parameter in an imported function without putting it as input. For instance:
# in def_function.py
def test(x):
parameter1 = 50 # default value
return parameter1*x
# in main.py
from def_function import test
print(test(1)) # It should give me 50
parameter1 = 10 # changing the value of parameter1 in test function
print(test(1)) # It should give me 10
parameter1 inside the function is in its own scope. It's not the same as the parameter1 outside the function definition.
To do what you're trying to do, add a keyword argument to the function definition, providing a default value for the argument:
# in def_function.py
def test(x, parameter1=50):
return parameter1*x
# in main.py
from def_function import test
print(test(1)) # It gives 50
print(test(1, parameter1=10)) # It gives 10 (as a keyword arg)
print(test(1, 10)) # It gives 10 (as a positional arg)
Don't use globals if you can help it.
Another option is to use the nonlocal keyword. You could do this in your code like this:
def main():
def test(x):
nonlocal parameter1
return parameter1*x
parameter1 = 50 # default value
print(test(1)) # It should give me 50
parameter1 = 10 # changing the value of parameter1 in test function
print(test(1)) # It should give me 10
main()
Read more here: https://www.w3schools.com/python/ref_keyword_nonlocal.asp
parameter1inmain.pyis unrelated toparameter1inside thetestfunction indef_function.py.x.def test(x, parameter1=50). If you call the function without a second parameter it will use the default value of50.def test(x, parameter1=50)and if you need a differentparameter1just usetest(1, 10).