How to create a python dict with a default value from a list?

Question

I have a list of names (say months) in a list. How can I create a dict with same value (say 0) without a comprehension if it is possible in some way?

months = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun']

What need is:

months_values = {'Jan': 0, 'Feb': 0, 'Mar': 0, 'Apr': 0, 'May': 0, 'Jun': 0}

lvzxy · Accepted Answer · 2019-09-17 03:28:13Z

2

months = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun']
months_dict = dict.fromkeys(months,0)

answered Sep 17, 2019 at 3:28

lvzxy

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Prem Jogi · Accepted Answer · 2019-09-17 03:33:27Z

1

month = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun']
dict1=dict.fromkeys(months,0)
print(dict1)

answered Sep 17, 2019 at 3:33

Prem Jogi

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