I have the following string to split into two columns:
Given:
DECLARE @String VARCHAR(MAX) = 'Mak^1,Jak^2,Smith^3,Lee^4,Joseph^5'
I want to split it into two columns:
column1 column2
-----------------
Mak 1
Jak 2
Smith 3
Lee 4
Joseph 5
My try:
Table-valued Function:
CREATE FUNCTION [dbo].[udf_Split]
(
@InputString VARCHAR(8000),
@Delimiter VARCHAR(50)
)
RETURNS @Items TABLE (ID INTEGER IDENTITY(1,1), Item VARCHAR(8000))
AS
BEGIN
IF @Delimiter = ' '
BEGIN
SET @Delimiter = ','
SET @InputString = REPLACE(@InputString, ' ', @Delimiter)
END
IF (@Delimiter IS NULL OR @Delimiter = '')
SET @Delimiter = ','
DECLARE @Item VARCHAR(8000)
DECLARE @ItemList VARCHAR(8000)
DECLARE @DelimIndex INT
SET @ItemList = @InputString
SET @DelimIndex = CHARINDEX(@Delimiter, @ItemList, 0)
WHILE (@DelimIndex != 0)
BEGIN
SET @Item = SUBSTRING(@ItemList, 0, @DelimIndex)
INSERT INTO @Items VALUES (@Item)
SET @ItemList = SUBSTRING(@ItemList, @DelimIndex+1, LEN(@ItemList)-@DelimIndex)
SET @DelimIndex = CHARINDEX(@Delimiter, @ItemList, 0)
END -- End WHILE
IF @Item IS NOT NULL
BEGIN
SET @Item = @ItemList
INSERT INTO @Items VALUES (@Item)
END
ELSE INSERT INTO @Items VALUES (@InputString)
RETURN
END
Function calling:
SELECT Item FROM [dbo].[udf_Split](@String ,',');
Output:
Item
--------------
Mak^1
Jak^2
Smith^3
Lee^4
Joseph^5
SELECT LEFT(Item, CHARINDEX('^', Item) - 1) AS Column1, RIGHT(Item, LEN(Item) - CHARINDEX('^', Item)) AS Column2 FROM [dbo].[udf_Split](@String ,',')will be enough.