This works:
Suppose I want to use in an ArrayFormula() the indirect() function, which doesn't work. That is, supposed I type this in cell E1, =ArrayFormula(indirect(address(row(E:E),column(A:A)))), this will return the value of cell A1 in all the cells in column E. To circumvent this, I created the custom function below:
function retValue(cell){
if(cell.map) {
return cell.map(retValue);
} else {
var cellRang = SpreadsheetApp.getActive().getRange(cell);
return cellRang.getValue();
}
}
Now, when I enter this =ArrayFormula(retValue(address(row(E:E),column(A:A)))) in cell E1, each cell in column E will have the corresponding value of the cell in the same row of column A.
My problem:
What I need is to have a custom function that receives 2 arguments, like function retValue2(cell, anotherRange) but I only care if cell is an array, as anotherRange must be an array anyway. What happens is that when I iteratively call cell.map(retValue2) the argument anotherRange is lost and I'm not entirely sure how to go about this.
I tried to come up with this:
function retValue2(cell, anotherRange) {
if (cell.map) {
return cell.map(retValue2);
} else {
var range = SpreadsheetApp.getActive().getRange(anotherRange);
var nrRows = range.getNumRows();
var nrCols = range.getNumColumns();
return cell + ',' + nrRows + ',' + nrCols;
}
}
But it fails because anotherRange is not recognized inside the iteration I think. How do I solve this?
PS.: in the example that works, why exactly does it work at all? I understand that when I do this return cell.map(retValue); it will use my own function as the callback, which would return all the values in the array, but in the spreadsheet it shows only the one on the same row. What is the magic here?
EDIT:
My end goal is to create my own lookup function where I pass a search key and a 2-dimensional array (rows and columns) and then, it locates the coordinates of that key in the array.
Look here:
function retCoord(sKey, sIRange) {
try {
var key = SpreadsheetApp.getActive().getRange(sKey).getValue();
}
catch(e) {
var key = sKey;
}
var range = SpreadsheetApp.getActive().getRange(sIRange).getValues();
nbRow = range.length;
nbColumn = range[0].length;
for(var i = 0; i<nbRow; i++){
for(var j = 0; j<nbColumn; j++){
if(range[i][j] == key){
return i + ", " + j;
}
}
}
}
If in my spreadsheet I enter something like =retCoord("K4","A:L") it will search the content of cell K4 in my 2-dimensional array A:L and return where in the array the value is, 1, 2 for example. It also works if I use =retCoord(K4,"A:L") or =retCoord("term searched","A:L"), and in this latter case I enter directly the term searched. This works fine until I use it in an ArrayFormula().
First, instead of =retCoord("K4","A:L") I could very well use =retCoord(address(4, 11),"A:L") for instance and my .getRange() method would get the cell K4 just fine.
Now, here is the big problem. I want to use my function in an ArrayFormula(), and, positioning my cursor in O1 and hoping to search the items from column D in the columns E through L I want to pass as one of the inputs of address(), row(O:O), like this: =ArrayFormula(retCoord(address(row(O:O),4,4),"E:L")), meaning that for each row, a new address is passed. that is, in O1 cell, it should return the result of retCoord(D1,"E:L"), in O2 should be retCoord(D2,"E:L"), in O3 should be retCoord(D3,"E:L") and so on.
The issue happens because in my function, sKey is an array and if I try to use the same approach as my function retValue (here above in the This works: section) it fails because now, in retCoord, I have 2 inputs, and the introspection function calling from before fails because of the second input. Of course I'm missing something and there is always a better and more elegant way to approach a problem. But for now, can anyone help me with this one?
EDIT2:
I changed the code a little and it seems I moved forward but not quite yet. Check comment below for line indicated by (*):
function retCoord(sKey, sIRange) {
var key = '';
try {
key = SpreadsheetApp.getActive().getRange(sKey).getValue();
return key;
}
catch(e) {
if (sKey.map) {
var objKey = sKey.map(retCoord);
return objKey; // (*) <--- comments below
key = objKey;
} else {
key = sKey;
}
}
var range = SpreadsheetApp.getActive().getRange(sIRange).getValues();
nbRow = range.length;
nbColumn = range[0].length;
for(var i = 0; i<nbRow; i++){
for(var j = 0; j<nbColumn; j++){
if(range[i][j] == key){
return key + " = "+ i + ", " + j;
}
}
}
}
This (*) line I added only to see what was returning from the map. Surprisingly (in a way), it is an object with all the elements of that column and that is expected. What I didn't expect was that if I return that object to my spreadsheet cell, it brings back only the value of that specific cell (as I wanted but not really as expected). But the problem is I cannot use that object to compare against a string as it will expand and become something else and will never match. Look:
- If I do
return objKeyin my custom function, over cell O1 it returns "a", in O2 it returns "b", in O3 it returns "c" as expected because those are the values of my cells D1, D2, D3 respectively. - If I do
return "-> " + objKeyin in my custom function, instead of returning-> a,-> b,-> cin O1, O2, O3 respectively, it returns-> =A:A,a,b,c,d,e,ffor all the cells incolumn O, which seems it did some type ofobjKey.toString()under the hood before concatenating with "-> "
Conclusion: how do I "coerce" the apparent result of objKey into string keeping the apparent result when you return the object without changing it? Simply put, I want the concatenation "some string" + to be equal to "some string" + "one string representing the value in that row instead of an object". In other words, what the hell is happening here? How does Google Sheets now that in that row, that element is the one representing the one I want? This is what I asked in the "PS." in the first part of this post.